Limit Comparison Test |
Suppose |
This test is more useful than the "direct" comparison test because you do not need to compare the terms of two series too carefully. It is sufficient if the two terms behave similar "in the long run".
Proof:
Examples 4.2.6:
Use the limit convergence test to decide whether the following series converge or diverge. Note that you need to know convergence of the p-series .
- Does the series
converge or diverge ?
- Does the series
converge of diverge ?
- If r(n) = p(n) / q(n), where p and q are polynomials in n, can you find general criteria for the series
p(n) to converge or diverge ?
Since
r = lim | a n / b n |
exists, and r is between 0 and infinity there exist
constants c and C,
0 < c < C <
such that for some positive integer N we have:
c < | a n / b n | < Cif n > N. Assume
converges absolutely. From above we have that
c | b n | < | an |for n > N. Hence,
converges absolutely by the comparison test.
Assume
converges absolutely. From above we have that
|a n | < C | b n |for n > N. But since the series C
also converges absolutely, we can use again the comparison test to see
that
must converge absolutely.
